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Interesting call

Discussion in 'Softball Forum' started by softballjunkie, May 21, 2007.

  1. May 21, 2007 at 10:07 AM #1
    softballjunkie

    softballjunkie Full Access Member

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    I saw a great NCAA game this weekend. But an interesting call was made in the 7th inning. Bases loaded, 1 out. The score is 4-2. The team behind is batting. Batter hits the ball sharply to 1st base. The 1st baseman fields the grounder and promptly runs towards the batter. The batter stops 1/3 of the way to 1st. As the batter is approached she takes 1 step back. The runner on 3rd scores. The plate umpire makes a call that since the batter took one step backward the play is ruled dead and no runner may advance. Was this the correct call? If so is this this rule for any base where a force play is intact? I've never seen this call made before. Is this true for HS ball as well?
     
  2. May 21, 2007 at 10:11 AM #2
    WndMillR

    WndMillR Full Access Member

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    Ump got it Right...

    Bingo.... Absolutely correct...
     
  3. May 21, 2007 at 10:21 AM #3
    WndMillR

    WndMillR Full Access Member

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    Ooops... didn't see the 2nd part of your post.

    Only applies from home plate to first.....

    a runner can return to any other base without penalty.
     
  4. May 21, 2007 at 10:23 AM #4
    Abbey fan

    Abbey fan Full Access Member

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    Great

    Great game, right call. Good to see U posting Charlie! Hope all is well. See U this summer
     
  5. May 21, 2007 at 3:13 PM #5
    softballjunkie

    softballjunkie Full Access Member

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    Even if it is a force play with the runner on first? That runner cannot go back to first on ground ball.
     
  6. May 21, 2007 at 3:39 PM #6
    homerun

    homerun Full Access Member

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    Runner on first
    grounder hit to first
    First steps on first for the out
    First baseman throws to second before runner gets there
    Are you saying runner cannot return to unoccupied first base?
     
  7. May 21, 2007 at 4:12 PM #7
    VoiceintheCrowd

    VoiceintheCrowd ND Announcer

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    Getting the first out at first removes the force

    I always thought that if you got the out at first first...that took the force off of the runner advancing to second...therfore the runner advancing to second has to be tagged out. If that's the case, the runner has every right to return to first.
     
  8. May 21, 2007 at 5:23 PM #8
    coach1320

    coach1320 Full Access Member

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    Voice is correct

    Voice,

    You are correct...if the fielder does not throw to 2nd first, the force is removed and the runner on 1st is allowed to return to 1st. You must get the lead runner 1st for the 2nd out to be automatic.

    As for the play in the UCLA/LMU game...it was the correct call by the umpire. The batter/runner between home and first can stop but cannot go backwards. As soon as she takes a step backwards, it becomes an immediate dead ball and all runners must return to their previous bases. The reason is you cannot return to home plate and be safe.
     
  9. May 21, 2007 at 7:12 PM #9
    softballjunkie

    softballjunkie Full Access Member

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    Gotcha

    I understand now. Home to first is a one way street!
     
  10. May 21, 2007 at 7:22 PM #10
    softballjunkie

    softballjunkie Full Access Member

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    Reason

    the reason I asked was because a few years ago I had the same play happen to me ( my team) during a baseball game inwhich my 1st baseman came up with the ball (he's playing in front of the bag) went toward the runner going to 1st. The runner goes backward, my 1st baseman, not sure what to do saw the runner comming from third to home and throws home never tagging the runner going to 1st. My catcher touches home plate figuring that since the runner was never tagged out it was a force play. The umpire immediatly called the runner out that was going to 1st, but allowed the run to score because he deemed that the play at home was no longer a force play. We end up losing the game. Either he was wrong or softball has a different rule, Thanks everybody.
     

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